1+3(3x-2)=-40+4x

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Solution for 1+3(3x-2)=-40+4x equation: 



1+3(3x-2)=-40+4x

We move all terms to the left:

1+3(3x-2)-(-40+4x)=0

We add all the numbers together, and all the variables

3(3x-2)-(4x-40)+1=0

We multiply parentheses

9x-(4x-40)-6+1=0

We get rid of parentheses

9x-4x+40-6+1=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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