1+3(5x+4)=-(x+1)+6(2x-1)

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Solution for 1+3(5x+4)=-(x+1)+6(2x-1) equation: 



1+3(5x+4)=-(x+1)+6(2x-1)

We move all terms to the left:

1+3(5x+4)-(-(x+1)+6(2x-1))=0

We multiply parentheses

15x-(-(x+1)+6(2x-1))+12+1=0



We calculate terms in parentheses: -(-(x+1)+6(2x-1)), so:

-(x+1)+6(2x-1)

We multiply parentheses

-(x+1)+12x-6

We get rid of parentheses

-x+12x-1-6

We add all the numbers together, and all the variables

11x-7

Back to the equation:

-(11x-7)



We add all the numbers together, and all the variables

15x-(11x-7)+13=0

We get rid of parentheses

15x-11x+7+13=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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