1+3(b+6)=1/4b+8

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Solution for 1+3(b+6)=1/4b+8 equation: 


b in (-oo:+oo)

3*(b+6)+1 = (1/4)*b+8 // - (1/4)*b+8

3*(b+6)-((1/4)*b)-8+1 = 0

3*(b+6)+(-1/4)*b-8+1 = 0

3*(b+6)-b/4-8+1 = 0

(3*4*(b+6))/4-b/4+(-8*4)/4+(1*4)/4 = 0

3*4*(b+6)-b-8*4+1*4 = 0

11*b-32+4+72 = 0

11*b+4+40 = 0

11*b+44 = 0

(11*b+44)/4 = 0

(11*b+44)/4 = 0 // * 4

11*b+44 = 0

11*b+44 = 0 // - 44

11*b = -44 // : 11

b = -44/11

b = -4

b = -4

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