1+3(c-1)-4(2c-5)=0

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Solution for 1+3(c-1)-4(2c-5)=0 equation:


Simplifying
1 + 3(c + -1) + -4(2c + -5) = 0

Reorder the terms:
1 + 3(-1 + c) + -4(2c + -5) = 0
1 + (-1 * 3 + c * 3) + -4(2c + -5) = 0
1 + (-3 + 3c) + -4(2c + -5) = 0

Reorder the terms:
1 + -3 + 3c + -4(-5 + 2c) = 0
1 + -3 + 3c + (-5 * -4 + 2c * -4) = 0
1 + -3 + 3c + (20 + -8c) = 0

Reorder the terms:
1 + -3 + 20 + 3c + -8c = 0

Combine like terms: 1 + -3 = -2
-2 + 20 + 3c + -8c = 0

Combine like terms: -2 + 20 = 18
18 + 3c + -8c = 0

Combine like terms: 3c + -8c = -5c
18 + -5c = 0

Solving
18 + -5c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + -5c = 0 + -18

Combine like terms: 18 + -18 = 0
0 + -5c = 0 + -18
-5c = 0 + -18

Combine like terms: 0 + -18 = -18
-5c = -18

Divide each side by '-5'.
c = 3.6

Simplifying
c = 3.6

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