1+3(d+2)=d+2(d-4)

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Solution for 1+3(d+2)=d+2(d-4) equation:


Simplifying
1 + 3(d + 2) = d + 2(d + -4)

Reorder the terms:
1 + 3(2 + d) = d + 2(d + -4)
1 + (2 * 3 + d * 3) = d + 2(d + -4)
1 + (6 + 3d) = d + 2(d + -4)

Combine like terms: 1 + 6 = 7
7 + 3d = d + 2(d + -4)

Reorder the terms:
7 + 3d = d + 2(-4 + d)
7 + 3d = d + (-4 * 2 + d * 2)
7 + 3d = d + (-8 + 2d)

Reorder the terms:
7 + 3d = -8 + d + 2d

Combine like terms: d + 2d = 3d
7 + 3d = -8 + 3d

Add '-3d' to each side of the equation.
7 + 3d + -3d = -8 + 3d + -3d

Combine like terms: 3d + -3d = 0
7 + 0 = -8 + 3d + -3d
7 = -8 + 3d + -3d

Combine like terms: 3d + -3d = 0
7 = -8 + 0
7 = -8

Solving
7 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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