1+3(r-8)-4(r+4)=

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Solution for 1+3(r-8)-4(r+4)= equation:


Simplifying
1 + 3(r + -8) + -4(r + 4) = 0

Reorder the terms:
1 + 3(-8 + r) + -4(r + 4) = 0
1 + (-8 * 3 + r * 3) + -4(r + 4) = 0
1 + (-24 + 3r) + -4(r + 4) = 0

Reorder the terms:
1 + -24 + 3r + -4(4 + r) = 0
1 + -24 + 3r + (4 * -4 + r * -4) = 0
1 + -24 + 3r + (-16 + -4r) = 0

Reorder the terms:
1 + -24 + -16 + 3r + -4r = 0

Combine like terms: 1 + -24 = -23
-23 + -16 + 3r + -4r = 0

Combine like terms: -23 + -16 = -39
-39 + 3r + -4r = 0

Combine like terms: 3r + -4r = -1r
-39 + -1r = 0

Solving
-39 + -1r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '39' to each side of the equation.
-39 + 39 + -1r = 0 + 39

Combine like terms: -39 + 39 = 0
0 + -1r = 0 + 39
-1r = 0 + 39

Combine like terms: 0 + 39 = 39
-1r = 39

Divide each side by '-1'.
r = -39

Simplifying
r = -39

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