1+3(x+2)=5(1+8x)

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Solution for 1+3(x+2)=5(1+8x) equation: 



1+3(x+2)=5(1+8x)

We move all terms to the left:

1+3(x+2)-(5(1+8x))=0

We add all the numbers together, and all the variables

3(x+2)-(5(8x+1))+1=0

We multiply parentheses

3x-(5(8x+1))+6+1=0



We calculate terms in parentheses: -(5(8x+1)), so:

5(8x+1)

We multiply parentheses

40x+5

Back to the equation:

-(40x+5)



We add all the numbers together, and all the variables

3x-(40x+5)+7=0

We get rid of parentheses

3x-40x-5+7=0

We add all the numbers together, and all the variables

-37x+2=0

We move all terms containing x to the left, all other terms to the right

-37x=-2

x=-2/-37

x=2/37

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