1+3(x-2)=7-5x

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Solution for 1+3(x-2)=7-5x equation: 



1+3(x-2)=7-5x

We move all terms to the left:

1+3(x-2)-(7-5x)=0

We add all the numbers together, and all the variables

3(x-2)-(-5x+7)+1=0

We multiply parentheses

3x-(-5x+7)-6+1=0

We get rid of parentheses

3x+5x-7-6+1=0

We add all the numbers together, and all the variables

8x-12=0

We move all terms containing x to the left, all other terms to the right

8x=12

x=12/8

x=1+1/2

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