1+3/4(x-2)=2/3(x+1)

Solution for 1+3/4(x-2)=2/3(x+1) equation:

1+3/4(x-2)=2/3(x+1)

We move all terms to the left:

1+3/4(x-2)-(2/3(x+1))=0


Domain of the equation: 4(x-2)!=0

x∈R



Domain of the equation: 3(x+1))!=0

x∈R


We calculate fractions


(9xx/(4(x-2)*3(x+1)))+(-8xx/(4(x-2)*3(x+1)))+1=0


We calculate terms in parentheses: +(9xx/(4(x-2)*3(x+1))), so:

9xx/(4(x-2)*3(x+1))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-8xx/(4(x-2)*3(x+1))), so:

-8xx/(4(x-2)*3(x+1))

We multiply all the terms by the denominator


-8xx

Back to the equation:

+(-8xx)


We get rid of parentheses

9xx-8xx+1=0

We move all terms containing x to the left, all other terms to the right

9xx-8xx=-1