1+3/4y=7

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Solution for 1+3/4y=7 equation: 



1+3/4y=7

We move all terms to the left:

1+3/4y-(7)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We add all the numbers together, and all the variables

3/4y-6=0

We multiply all the terms by the denominator


-6*4y+3=0

Wy multiply elements

-24y+3=0

We move all terms containing y to the left, all other terms to the right

-24y=-3

y=-3/-24

y=1/8

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