1+3b+(3-2b)5=38

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Solution for 1+3b+(3-2b)5=38 equation: 



1+3b+(3-2b)5=38

We move all terms to the left:

1+3b+(3-2b)5-(38)=0

We add all the numbers together, and all the variables

3b+(-2b+3)5+1-38=0

We add all the numbers together, and all the variables

3b+(-2b+3)5-37=0

We multiply parentheses

3b-10b+15-37=0

We add all the numbers together, and all the variables

-7b-22=0

We move all terms containing b to the left, all other terms to the right

-7b=22

b=22/-7

b=-3+1/7

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