1+3b=8(b-2)

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Solution for 1+3b=8(b-2) equation: 



1+3b=8(b-2)

We move all terms to the left:

1+3b-(8(b-2))=0



We calculate terms in parentheses: -(8(b-2)), so:

8(b-2)

We multiply parentheses

8b-16

Back to the equation:

-(8b-16)



We get rid of parentheses

3b-8b+16+1=0

We add all the numbers together, and all the variables

-5b+17=0

We move all terms containing b to the left, all other terms to the right

-5b=-17

b=-17/-5

b=3+2/5

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