1+3c=5(1-c)=8C

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Solution for 1+3c=5(1-c)=8C equation: 



1+3c=5(1-c)=8

We move all terms to the left:

1+3c-(5(1-c))=0

We add all the numbers together, and all the variables

3c-(5(-1c+1))+1=0



We calculate terms in parentheses: -(5(-1c+1)), so:

5(-1c+1)

We multiply parentheses

-5c+5

Back to the equation:

-(-5c+5)



We get rid of parentheses

3c+5c-5+1=0

We add all the numbers together, and all the variables

8c-4=0

We move all terms containing c to the left, all other terms to the right

8c=4

c=4/8

c=1/2

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