1+3m+m+2=4(m-6)+3(m+8)

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Solution for 1+3m+m+2=4(m-6)+3(m+8) equation: 



1+3m+m+2=4(m-6)+3(m+8)

We move all terms to the left:

1+3m+m+2-(4(m-6)+3(m+8))=0

We add all the numbers together, and all the variables

4m-(4(m-6)+3(m+8))+3=0



We calculate terms in parentheses: -(4(m-6)+3(m+8)), so:

4(m-6)+3(m+8)

We multiply parentheses

4m+3m-24+24

We add all the numbers together, and all the variables

7m

Back to the equation:

-(7m)



We add all the numbers together, and all the variables

-3m+3=0

We move all terms containing m to the left, all other terms to the right

-3m=-3

m=-3/-3

m=1

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