1+3r=6(1-6r)-5

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Solution for 1+3r=6(1-6r)-5 equation: 



1+3r=6(1-6r)-5

We move all terms to the left:

1+3r-(6(1-6r)-5)=0

We add all the numbers together, and all the variables

3r-(6(-6r+1)-5)+1=0



We calculate terms in parentheses: -(6(-6r+1)-5), so:

6(-6r+1)-5

We multiply parentheses

-36r+6-5

We add all the numbers together, and all the variables

-36r+1

Back to the equation:

-(-36r+1)



We get rid of parentheses

3r+36r-1+1=0

We add all the numbers together, and all the variables

39r=0

r=0/39

r=0

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