1+3x=8(2x+4)-7

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Solution for 1+3x=8(2x+4)-7 equation: 



1+3x=8(2x+4)-7

We move all terms to the left:

1+3x-(8(2x+4)-7)=0



We calculate terms in parentheses: -(8(2x+4)-7), so:

8(2x+4)-7

We multiply parentheses

16x+32-7

We add all the numbers together, and all the variables

16x+25

Back to the equation:

-(16x+25)



We get rid of parentheses

3x-16x-25+1=0

We add all the numbers together, and all the variables

-13x-24=0

We move all terms containing x to the left, all other terms to the right

-13x=24

x=24/-13

x=-1+11/13

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