1+4(2c-3)=3(3c-5)

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Solution for 1+4(2c-3)=3(3c-5) equation:


Simplifying
1 + 4(2c + -3) = 3(3c + -5)

Reorder the terms:
1 + 4(-3 + 2c) = 3(3c + -5)
1 + (-3 * 4 + 2c * 4) = 3(3c + -5)
1 + (-12 + 8c) = 3(3c + -5)

Combine like terms: 1 + -12 = -11
-11 + 8c = 3(3c + -5)

Reorder the terms:
-11 + 8c = 3(-5 + 3c)
-11 + 8c = (-5 * 3 + 3c * 3)
-11 + 8c = (-15 + 9c)

Solving
-11 + 8c = -15 + 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
-11 + 8c + -9c = -15 + 9c + -9c

Combine like terms: 8c + -9c = -1c
-11 + -1c = -15 + 9c + -9c

Combine like terms: 9c + -9c = 0
-11 + -1c = -15 + 0
-11 + -1c = -15

Add '11' to each side of the equation.
-11 + 11 + -1c = -15 + 11

Combine like terms: -11 + 11 = 0
0 + -1c = -15 + 11
-1c = -15 + 11

Combine like terms: -15 + 11 = -4
-1c = -4

Divide each side by '-1'.
c = 4

Simplifying
c = 4

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