1+4(3-x)=2(x-2)+5

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Solution for 1+4(3-x)=2(x-2)+5 equation: 



1+4(3-x)=2(x-2)+5

We move all terms to the left:

1+4(3-x)-(2(x-2)+5)=0

We add all the numbers together, and all the variables

4(-1x+3)-(2(x-2)+5)+1=0

We multiply parentheses

-4x-(2(x-2)+5)+12+1=0



We calculate terms in parentheses: -(2(x-2)+5), so:

2(x-2)+5

We multiply parentheses

2x-4+5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-4x-(2x+1)+13=0

We get rid of parentheses

-4x-2x-1+13=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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