1+4(3k+3)=49

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Solution for 1+4(3k+3)=49 equation: 



1+4(3k+3)=49

We move all terms to the left:

1+4(3k+3)-(49)=0

We add all the numbers together, and all the variables

4(3k+3)-48=0

We multiply parentheses

12k+12-48=0

We add all the numbers together, and all the variables

12k-36=0

We move all terms containing k to the left, all other terms to the right

12k=36

k=36/12

k=3

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