1+4(8c-6)=-6c-10-1

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Solution for 1+4(8c-6)=-6c-10-1 equation: 



1+4(8c-6)=-6c-10-1

We move all terms to the left:

1+4(8c-6)-(-6c-10-1)=0

We add all the numbers together, and all the variables

4(8c-6)-(-6c-11)+1=0

We multiply parentheses

32c-(-6c-11)-24+1=0

We get rid of parentheses

32c+6c+11-24+1=0

We add all the numbers together, and all the variables

38c-12=0

We move all terms containing c to the left, all other terms to the right

38c=12

c=12/38

c=6/19

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