1+4m+6m=3(7m-8)-7(m-7)

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Solution for 1+4m+6m=3(7m-8)-7(m-7) equation: 



1+4m+6m=3(7m-8)-7(m-7)

We move all terms to the left:

1+4m+6m-(3(7m-8)-7(m-7))=0

We add all the numbers together, and all the variables

10m-(3(7m-8)-7(m-7))+1=0



We calculate terms in parentheses: -(3(7m-8)-7(m-7)), so:

3(7m-8)-7(m-7)

We multiply parentheses

21m-7m-24+49

We add all the numbers together, and all the variables

14m+25

Back to the equation:

-(14m+25)



We get rid of parentheses

10m-14m-25+1=0

We add all the numbers together, and all the variables

-4m-24=0

We move all terms containing m to the left, all other terms to the right

-4m=24

m=24/-4

m=-6

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