1+4v+2=5(6v-2)-3(8v-5)

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Solution for 1+4v+2=5(6v-2)-3(8v-5) equation: 



1+4v+2=5(6v-2)-3(8v-5)

We move all terms to the left:

1+4v+2-(5(6v-2)-3(8v-5))=0

We add all the numbers together, and all the variables

4v-(5(6v-2)-3(8v-5))+3=0



We calculate terms in parentheses: -(5(6v-2)-3(8v-5)), so:

5(6v-2)-3(8v-5)

We multiply parentheses

30v-24v-10+15

We add all the numbers together, and all the variables

6v+5

Back to the equation:

-(6v+5)



We get rid of parentheses

4v-6v-5+3=0

We add all the numbers together, and all the variables

-2v-2=0

We move all terms containing v to the left, all other terms to the right

-2v=2

v=2/-2

v=-1

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