1+4v=6v+7(v+4)

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Solution for 1+4v=6v+7(v+4) equation: 



1+4v=6v+7(v+4)

We move all terms to the left:

1+4v-(6v+7(v+4))=0



We calculate terms in parentheses: -(6v+7(v+4)), so:

6v+7(v+4)

We multiply parentheses

6v+7v+28

We add all the numbers together, and all the variables

13v+28

Back to the equation:

-(13v+28)



We get rid of parentheses

4v-13v-28+1=0

We add all the numbers together, and all the variables

-9v-27=0

We move all terms containing v to the left, all other terms to the right

-9v=27

v=27/-9

v=-3

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