1+4x/3x=4-2x/5x

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Solution for 1+4x/3x=4-2x/5x equation: 



1+4x/3x=4-2x/5x

We move all terms to the left:

1+4x/3x-(4-2x/5x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x/3x-(-2x/5x+4)+1=0

We get rid of parentheses

4x/3x+2x/5x-4+1=0

We calculate fractions


20x^2/15x^2+6x^2/15x^2-4+1=0

We add all the numbers together, and all the variables

20x^2/15x^2+6x^2/15x^2-3=0

We multiply all the terms by the denominator


20x^2+6x^2-3*15x^2=0

We add all the numbers together, and all the variables

26x^2-3*15x^2=0

Wy multiply elements

26x^2-45x^2=0

We add all the numbers together, and all the variables

-19x^2=0

a = -19; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-19)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-38}=0$

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