1+5(2x+3)=16x-2(3x+8)

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Solution for 1+5(2x+3)=16x-2(3x+8) equation:


Simplifying
1 + 5(2x + 3) = 16x + -2(3x + 8)

Reorder the terms:
1 + 5(3 + 2x) = 16x + -2(3x + 8)
1 + (3 * 5 + 2x * 5) = 16x + -2(3x + 8)
1 + (15 + 10x) = 16x + -2(3x + 8)

Combine like terms: 1 + 15 = 16
16 + 10x = 16x + -2(3x + 8)

Reorder the terms:
16 + 10x = 16x + -2(8 + 3x)
16 + 10x = 16x + (8 * -2 + 3x * -2)
16 + 10x = 16x + (-16 + -6x)

Reorder the terms:
16 + 10x = -16 + 16x + -6x

Combine like terms: 16x + -6x = 10x
16 + 10x = -16 + 10x

Add '-10x' to each side of the equation.
16 + 10x + -10x = -16 + 10x + -10x

Combine like terms: 10x + -10x = 0
16 + 0 = -16 + 10x + -10x
16 = -16 + 10x + -10x

Combine like terms: 10x + -10x = 0
16 = -16 + 0
16 = -16

Solving
16 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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