1+5(4n-7)=(7n-3)-30

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Solution for 1+5(4n-7)=(7n-3)-30 equation: 



1+5(4n-7)=(7n-3)-30

We move all terms to the left:

1+5(4n-7)-((7n-3)-30)=0

We multiply parentheses

20n-((7n-3)-30)-35+1=0



We calculate terms in parentheses: -((7n-3)-30), so:

(7n-3)-30

We get rid of parentheses

7n-3-30

We add all the numbers together, and all the variables

7n-33

Back to the equation:

-(7n-33)



We add all the numbers together, and all the variables

20n-(7n-33)-34=0

We get rid of parentheses

20n-7n+33-34=0

We add all the numbers together, and all the variables

13n-1=0

We move all terms containing n to the left, all other terms to the right

13n=1

n=1/13

n=1/13

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