1+5(6+8x)=-7(3-2x)

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Solution for 1+5(6+8x)=-7(3-2x) equation: 



1+5(6+8x)=-7(3-2x)

We move all terms to the left:

1+5(6+8x)-(-7(3-2x))=0

We add all the numbers together, and all the variables

5(8x+6)-(-7(-2x+3))+1=0

We multiply parentheses

40x-(-7(-2x+3))+30+1=0



We calculate terms in parentheses: -(-7(-2x+3)), so:

-7(-2x+3)

We multiply parentheses

14x-21

Back to the equation:

-(14x-21)



We add all the numbers together, and all the variables

40x-(14x-21)+31=0

We get rid of parentheses

40x-14x+21+31=0

We add all the numbers together, and all the variables

26x+52=0

We move all terms containing x to the left, all other terms to the right

26x=-52

x=-52/26

x=-2

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