1+5(x-4)=6x-2(x+2)

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Solution for 1+5(x-4)=6x-2(x+2) equation: 



1+5(x-4)=6x-2(x+2)

We move all terms to the left:

1+5(x-4)-(6x-2(x+2))=0

We multiply parentheses

5x-(6x-2(x+2))-20+1=0



We calculate terms in parentheses: -(6x-2(x+2)), so:

6x-2(x+2)

We multiply parentheses

6x-2x-4

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

5x-(4x-4)-19=0

We get rid of parentheses

5x-4x+4-19=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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