1+5/(2x0)

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Solution for 1+5/(2x0) equation: 


D( x )

x = 0

2*x^0 = 0

x = 0

x = 0

2*x^0 = 0

2*x^0 = 0

2 = 0

x^0 = 0

1 = 0

x^0 = 0

1 = 0

x belongs to the empty set

2*x^0 = 0  <=>  2 = 0 or 2*x^0 = 0  <=>  x^0 = 0

x in (-oo:0) U (0:+oo)

5/(2*x^0)+1 = 0

5/2+1 = 0

7/2 = 0

x belongs to the empty set

x belongs to the empty set

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