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1+5/8x+3/2x=12
We move all terms to the left:
1+5/8x+3/2x-(12)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5/8x+3/2x-11=0
We calculate fractions
10x/16x^2+24x/16x^2-11=0
We multiply all the terms by the denominator
10x+24x-11*16x^2=0
We add all the numbers together, and all the variables
34x-11*16x^2=0
Wy multiply elements
-176x^2+34x=0
a = -176; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·(-176)·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*-176}=\frac{-68}{-352} =17/88 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*-176}=\frac{0}{-352} =0 $
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