1+6(y+3)=23

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Solution for 1+6(y+3)=23 equation: 



1+6(y+3)=23

We move all terms to the left:

1+6(y+3)-(23)=0

We add all the numbers together, and all the variables

6(y+3)-22=0

We multiply parentheses

6y+18-22=0

We add all the numbers together, and all the variables

6y-4=0

We move all terms containing y to the left, all other terms to the right

6y=4

y=4/6

y=2/3

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