1+6x/3+2(4x-2)=7

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Solution for 1+6x/3+2(4x-2)=7 equation:



1+6x/3+2(4x-2)=7
We move all terms to the left:
1+6x/3+2(4x-2)-(7)=0
We add all the numbers together, and all the variables
6x/3+2(4x-2)-6=0
We multiply parentheses
6x/3+8x-4-6=0
We multiply all the terms by the denominator
6x+8x*3-4*3-6*3=0
We add all the numbers together, and all the variables
6x+8x*3-30=0
Wy multiply elements
6x+24x-30=0
We add all the numbers together, and all the variables
30x-30=0
We move all terms containing x to the left, all other terms to the right
30x=30
x=30/30
x=1

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