1+8(x-5)=9-2(x-4)

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Solution for 1+8(x-5)=9-2(x-4) equation: 



1+8(x-5)=9-2(x-4)

We move all terms to the left:

1+8(x-5)-(9-2(x-4))=0

We multiply parentheses

8x-(9-2(x-4))-40+1=0



We calculate terms in parentheses: -(9-2(x-4)), so:

9-2(x-4)

determiningTheFunctionDomain
-2(x-4)+9

We multiply parentheses

-2x+8+9

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

8x-(-2x+17)-39=0

We get rid of parentheses

8x+2x-17-39=0

We add all the numbers together, and all the variables

10x-56=0

We move all terms containing x to the left, all other terms to the right

10x=56

x=56/10

x=5+3/5

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