1+8(x-8)=7-8(x-5)

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Solution for 1+8(x-8)=7-8(x-5) equation:



1+8(x-8)=7-8(x-5)
We move all terms to the left:
1+8(x-8)-(7-8(x-5))=0
We multiply parentheses
8x-(7-8(x-5))-64+1=0
We calculate terms in parentheses: -(7-8(x-5)), so:
7-8(x-5)
determiningTheFunctionDomain -8(x-5)+7
We multiply parentheses
-8x+40+7
We add all the numbers together, and all the variables
-8x+47
Back to the equation:
-(-8x+47)
We add all the numbers together, and all the variables
8x-(-8x+47)-63=0
We get rid of parentheses
8x+8x-47-63=0
We add all the numbers together, and all the variables
16x-110=0
We move all terms containing x to the left, all other terms to the right
16x=110
x=110/16
x=6+7/8

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