1+8k+1=11(k+1)-(4+k)

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Solution for 1+8k+1=11(k+1)-(4+k) equation: 



1+8k+1=11(k+1)-(4+k)

We move all terms to the left:

1+8k+1-(11(k+1)-(4+k))=0

We add all the numbers together, and all the variables

8k-(11(k+1)-(k+4))+1+1=0

We add all the numbers together, and all the variables

8k-(11(k+1)-(k+4))+2=0



We calculate terms in parentheses: -(11(k+1)-(k+4)), so:

11(k+1)-(k+4)

We multiply parentheses

11k-(k+4)+11

We get rid of parentheses

11k-k-4+11

We add all the numbers together, and all the variables

10k+7

Back to the equation:

-(10k+7)



We get rid of parentheses

8k-10k-7+2=0

We add all the numbers together, and all the variables

-2k-5=0

We move all terms containing k to the left, all other terms to the right

-2k=5

k=5/-2

k=-2+1/2

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