If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1+8x+16x^2=0
a = 16; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{32}=-1/4$
| 6+a/8=-1 | | 155=45-v | | 3.405-2.10q=0.17q | | 130+20+b=180 | | -1+a/3=5 | | (Y-6)(y+1)=0 | | b+60+78=180 | | 2/9x=-1/8x+2/9 | | 202=156-y | | 2x+73+71=180 | | 212+48h=-1 | | 6a−7=5a+2/a= | | 6a−7=5a+2a= | | 4x+10+103+31=180 | | 114-w=294 | | 3/4x-3/4x=0 | | 4x+10+103+32=180 | | 8.94=4.29+3x | | 124-v=207 | | 8.94=4.29=3x | | 4x+1+103+32=180 | | _1/3(6x+8)=10 | | P(x)=(x^6)-(x^5)+(4x^2)-4x | | 11x-4+86+32=180 | | 10(b+3)=160 | | 10(x+3)-9-9x-4)=x-5+3 | | 1.5x-1.7+2.44x=0.46 | | P(x)=x^6-x^5+4x^2-4x | | n/9=18/6 | | 6x+13+24+101=180 | | -3(x+5)=3(x+1 | | 1+3x+34+31=180 |