1+9(x-7)=1-8(x-2)

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Solution for 1+9(x-7)=1-8(x-2) equation: 



1+9(x-7)=1-8(x-2)

We move all terms to the left:

1+9(x-7)-(1-8(x-2))=0

We multiply parentheses

9x-(1-8(x-2))-63+1=0



We calculate terms in parentheses: -(1-8(x-2)), so:

1-8(x-2)

determiningTheFunctionDomain
-8(x-2)+1

We multiply parentheses

-8x+16+1

We add all the numbers together, and all the variables

-8x+17

Back to the equation:

-(-8x+17)



We add all the numbers together, and all the variables

9x-(-8x+17)-62=0

We get rid of parentheses

9x+8x-17-62=0

We add all the numbers together, and all the variables

17x-79=0

We move all terms containing x to the left, all other terms to the right

17x=79

x=79/17

x=4+11/17

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