1+cos(x)+cos(2x)cos(3x)=0

Simple and best practice solution for 1+cos(x)+cos(2x)cos(3x)=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 1+cos(x)+cos(2x)cos(3x)=0 equation: 


Simplifying
1 + cos(x) + cos(2x) * cos(3x) = 0

Multiply cos * x
1 + cosx + cos(2x) * cos(3x) = 0

Remove parenthesis around (2x)
1 + cosx + cos * 2x * cos(3x) = 0

Remove parenthesis around (3x)
1 + cosx + cos * 2x * cos * 3x = 0

Reorder the terms for easier multiplication:
1 + cosx + 2 * 3cos * x * cos * x = 0

Multiply 2 * 3
1 + cosx + 6cos * x * cos * x = 0

Multiply cos * x
1 + cosx + 6cosx * cos * x = 0

Multiply cosx * cos
1 + cosx + 6c2o2s2x * x = 0

Multiply c2o2s2x * x
1 + cosx + 6c2o2s2x2 = 0

Solving
1 + cosx + 6c2o2s2x2 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

See similar equations:

| -30=2b-10 | | f(x)=14/x2 | | 2+(x-6)+1=2x-5 | | 5(x-1)+3x+2=x-4(2x-3) | | 4+log^4(-5x)=6 | | 300e^2x=1200 | | (n-2)180=170n | | (x-11)2+(y+6)2=81 | | 20x^2-33x-36=0 | | 3(x+3)+3=2(x+8)+6 | | x^4+2x^2+6=0 | | 3x+13=-83-9 | | F=1/6 | | (-9x-8)-(-6x-7)= | | 15x^2-24=0 | | 160=[(n-2)180]/n | | 5u^2+2=-11u | | T(n)=n-4 | | 4(2c+8)=5c+20 | | p^2-p-27=-7 | | 12x+12y=1428 | | 14x-4=0 | | -48=x+48 | | 8(1-9y)=5(19-3y) | | 5x-5+4x+15+8x-10=360 | | 32x+7y=347 | | 3.2/2.4=6/x | | j(j+7)=0 | | -2(6x-12)=-48 | | 15=t+12 | | 37.5=5 | | 7x^2+7x-25=-1+6x^2 |

Equations solver categories