1+ln(x+1)=ln(x-1)

Solution for 1+ln(x+1)=ln(x-1) equation:

Simplifying
1 + ln(x + 1) = ln(x + -1)

Reorder the terms:
1 + ln(1 + x) = ln(x + -1)
1 + (1 * ln + x * ln) = ln(x + -1)
1 + (1ln + lnx) = ln(x + -1)

Reorder the terms:
1 + 1ln + lnx = ln(-1 + x)
1 + 1ln + lnx = (-1 * ln + x * ln)
1 + 1ln + lnx = (-1ln + lnx)

Add '-1lnx' to each side of the equation.
1 + 1ln + lnx + -1lnx = -1ln + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
1 + 1ln + 0 = -1ln + lnx + -1lnx
1 + 1ln = -1ln + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
1 + 1ln = -1ln + 0
1 + 1ln = -1ln

Solving
1 + 1ln = -1ln

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add 'ln' to each side of the equation.
1 + 1ln + ln = -1ln + ln

Combine like terms: 1ln + ln = 2ln
1 + 2ln = -1ln + ln

Combine like terms: -1ln + ln = 0
1 + 2ln = 0

Add '-1' to each side of the equation.
1 + -1 + 2ln = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2ln = 0 + -1
2ln = 0 + -1

Combine like terms: 0 + -1 = -1
2ln = -1

Divide each side by '2n'.
l = -0.5n-1

Simplifying
l = -0.5n-1