1+m=2(2m+1)

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Solution for 1+m=2(2m+1) equation: 



1+m=2(2m+1)

We move all terms to the left:

1+m-(2(2m+1))=0



We calculate terms in parentheses: -(2(2m+1)), so:

2(2m+1)

We multiply parentheses

4m+2

Back to the equation:

-(4m+2)



We get rid of parentheses

m-4m-2+1=0

We add all the numbers together, and all the variables

-3m-1=0

We move all terms containing m to the left, all other terms to the right

-3m=1

m=1/-3

m=-1/3

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