1+x(1-log(x))=0

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Solution for 1+x(1-log(x))=0 equation:


Simplifying
1 + x(1 + -1log(x)) = 0

Multiply glo * x
1 + x(1 + -1glox) = 0
1 + (1 * x + -1glox * x) = 0

Reorder the terms:
1 + (-1glox2 + 1x) = 0
1 + (-1glox2 + 1x) = 0

Solving
1 + -1glox2 + 1x = 0

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1glox2 + -1 + 1x = 0 + -1

Reorder the terms:
1 + -1 + -1glox2 + 1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1glox2 + 1x = 0 + -1
-1glox2 + 1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1glox2 + 1x = -1

Add '-1x' to each side of the equation.
-1glox2 + 1x + -1x = -1 + -1x

Combine like terms: 1x + -1x = 0
-1glox2 + 0 = -1 + -1x
-1glox2 = -1 + -1x

Divide each side by '-1lox2'.
g = l-1o-1x-2 + l-1o-1x-1

Simplifying
g = l-1o-1x-2 + l-1o-1x-1

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