1+x+10=2(x+4)-4(-3+x)

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Solution for 1+x+10=2(x+4)-4(-3+x) equation: 



1+x+10=2(x+4)-4(-3+x)

We move all terms to the left:

1+x+10-(2(x+4)-4(-3+x))=0

We add all the numbers together, and all the variables

x-(2(x+4)-4(x-3))+1+10=0

We add all the numbers together, and all the variables

x-(2(x+4)-4(x-3))+11=0



We calculate terms in parentheses: -(2(x+4)-4(x-3)), so:

2(x+4)-4(x-3)

We multiply parentheses

2x-4x+8+12

We add all the numbers together, and all the variables

-2x+20

Back to the equation:

-(-2x+20)



We get rid of parentheses

x+2x-20+11=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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