1+x-2-(3-x)=6-(1-1)

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Solution for 1+x-2-(3-x)=6-(1-1) equation:


Simplifying
1 + x + -2 + -1(3 + -1x) = 6 + -1(1 + -1)
1 + x + -2 + (3 * -1 + -1x * -1) = 6 + -1(1 + -1)
1 + x + -2 + (-3 + 1x) = 6 + -1(1 + -1)

Reorder the terms:
1 + -2 + -3 + x + 1x = 6 + -1(1 + -1)

Combine like terms: 1 + -2 = -1
-1 + -3 + x + 1x = 6 + -1(1 + -1)

Combine like terms: -1 + -3 = -4
-4 + x + 1x = 6 + -1(1 + -1)

Combine like terms: x + 1x = 2x
-4 + 2x = 6 + -1(1 + -1)

Combine like terms: 1 + -1 = 0
-4 + 2x = 6 + -1(0)

Multiply -1 * 0
-4 + 2x = 6 + 0

Anything times zero is zero.
-4 + 2x = 6 + 0

Combine like terms: 6 + 0 = 6
-4 + 2x = 6

Solving
-4 + 2x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2x = 6 + 4

Combine like terms: -4 + 4 = 0
0 + 2x = 6 + 4
2x = 6 + 4

Combine like terms: 6 + 4 = 10
2x = 10

Divide each side by '2'.
x = 5

Simplifying
x = 5

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