1+z(m+4)=29

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Solution for 1+z(m+4)=29 equation:


Simplifying
1 + z(m + 4) = 29

Reorder the terms:
1 + z(4 + m) = 29
1 + (4 * z + m * z) = 29

Reorder the terms:
1 + (mz + 4z) = 29
1 + (mz + 4z) = 29

Solving
1 + mz + 4z = 29

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + mz + -1 + 4z = 29 + -1

Reorder the terms:
1 + -1 + mz + 4z = 29 + -1

Combine like terms: 1 + -1 = 0
0 + mz + 4z = 29 + -1
mz + 4z = 29 + -1

Combine like terms: 29 + -1 = 28
mz + 4z = 28

Add '-4z' to each side of the equation.
mz + 4z + -4z = 28 + -4z

Combine like terms: 4z + -4z = 0
mz + 0 = 28 + -4z
mz = 28 + -4z

Divide each side by 'z'.
m = 28z-1 + -4

Simplifying
m = 28z-1 + -4

Reorder the terms:
m = -4 + 28z-1

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