1,2(x+1)-3=9-(3+0,3x)

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Solution for 1,2(x+1)-3=9-(3+0,3x) equation: 



1.2(x+1)-3=9-(3+0.3x)

We move all terms to the left:

1.2(x+1)-3-(9-(3+0.3x))=0

We add all the numbers together, and all the variables

1.2(x+1)-(9-(0.3x+3))-3=0

We multiply parentheses

1.2x-(9-(0.3x+3))+1.2-3=0



We calculate terms in parentheses: -(9-(0.3x+3)), so:

9-(0.3x+3)

determiningTheFunctionDomain
-(0.3x+3)+9

We get rid of parentheses

-0.3x-3+9

We add all the numbers together, and all the variables

-0.3x+6

Back to the equation:

-(-0.3x+6)



We add all the numbers together, and all the variables

1.2x-(-0.3x+6)-1.8=0

We get rid of parentheses

1.2x+0.3x-6-1.8=0

We add all the numbers together, and all the variables

1.5x-7.8=0

We move all terms containing x to the left, all other terms to the right

1.5x=7.8

x=7.8/1.5

x=5+0.3/1.5

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