1,3x-7,43=1,5x(2,5-2x)

Solution for 1,3x-7,43=1,5x(2,5-2x) equation:

1.3x-7.43=1.5x(2.5-2x)

We move all terms to the left:

1.3x-7.43-(1.5x(2.5-2x))=0

We add all the numbers together, and all the variables

1.3x-(1.5x(-2x+2.5))-7.43=0


We calculate terms in parentheses: -(1.5x(-2x+2.5)), so:

1.5x(-2x+2.5)

We multiply parentheses

-2x^2+2.5x

Back to the equation:

-(-2x^2+2.5x)


We get rid of parentheses

2x^2-2.5x+1.3x-7.43=0

We add all the numbers together, and all the variables

2x^2-1.2x-7.43=0

a = 2; b = -1.2; c = -7.43;
Δ = b2-4ac
Δ = -1.22-4·2·(-7.43)
Δ = 60.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{60.88}}{2*2}=\frac{1.2-\sqrt{60.88}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{60.88}}{2*2}=\frac{1.2+\sqrt{60.88}}{4}
$