1,4-5(0,6x-1,5)=7(0,2x+0,1)

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Solution for 1,4-5(0,6x-1,5)=7(0,2x+0,1) equation: 



1.4-5(0.6x-1.5)=7(0.2x+0.1)

We move all terms to the left:

1.4-5(0.6x-1.5)-(7(0.2x+0.1))=0

We multiply parentheses

-0x-(7(0.2x+0.1))+7.5+1.4=0



We calculate terms in parentheses: -(7(0.2x+0.1)), so:

7(0.2x+0.1)

We multiply parentheses

0x+0.7

We add all the numbers together, and all the variables

x+0.7

Back to the equation:

-(x+0.7)



We add all the numbers together, and all the variables

-1x-(x+0.7)+8.9=0

We get rid of parentheses

-1x-x-0.7+8.9=0

We add all the numbers together, and all the variables

-2x+8.2=0

We move all terms containing x to the left, all other terms to the right

-2x=-8.2

x=-8.2/-2

x=4+0.2/2

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