1,8-(2,2+4,2x)=-(3,9-4,7x)-(3,1x-11)

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Solution for 1,8-(2,2+4,2x)=-(3,9-4,7x)-(3,1x-11) equation:



1.8-(2.2+4.2x)=-(3.9-4.7x)-(3.1x-11)
We move all terms to the left:
1.8-(2.2+4.2x)-(-(3.9-4.7x)-(3.1x-11))=0
We add all the numbers together, and all the variables
-(4.2x+2.2)-(-(-4.7x+3.9)-(3.1x-11))+1.8=0
We get rid of parentheses
-4.2x-(-(-4.7x+3.9)-(3.1x-11))-2.2+1.8=0
We calculate terms in parentheses: -(-(-4.7x+3.9)-(3.1x-11)), so:
-(-4.7x+3.9)-(3.1x-11)
We get rid of parentheses
4.7x-3.1x-3.9+11
We add all the numbers together, and all the variables
1.6x+7.1
Back to the equation:
-(1.6x+7.1)
We add all the numbers together, and all the variables
-4.2x-(1.6x+7.1)-0.4=0
We get rid of parentheses
-4.2x-1.6x-7.1-0.4=0
We add all the numbers together, and all the variables
-5.8x-7.5=0
We move all terms containing x to the left, all other terms to the right
-5.8x=7.5
x=7.5/-5.8
x=-1+1/3.41176470588

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