1-(-3)=(x+x)-12+4x+8+8+(-x)

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Solution for 1-(-3)=(x+x)-12+4x+8+8+(-x) equation: 



1-(-3)=(x+x)-12+4x+8+8+(-x)

We move all terms to the left:

1-(-3)-((x+x)-12+4x+8+8+(-x))=0

We add all the numbers together, and all the variables

-((+2x)-12+4x+8+8+(-1x))+1-(-3)=0

We add all the numbers together, and all the variables

-((+2x)-12+4x+8+8+(-1x))+4=0



We calculate terms in parentheses: -((+2x)-12+4x+8+8+(-1x)), so:

(+2x)-12+4x+8+8+(-1x)

determiningTheFunctionDomain
(+2x)+4x+(-1x)-12+8+8

We add all the numbers together, and all the variables

4x+(+2x)+(-1x)+4

We get rid of parentheses

4x+2x-1x+4

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

-5x-4+4=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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