1-(2+w)=3(w+5)

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Solution for 1-(2+w)=3(w+5) equation: 



1-(2+w)=3(w+5)

We move all terms to the left:

1-(2+w)-(3(w+5))=0

We add all the numbers together, and all the variables

-(w+2)-(3(w+5))+1=0

We get rid of parentheses

-w-(3(w+5))-2+1=0



We calculate terms in parentheses: -(3(w+5)), so:

3(w+5)

We multiply parentheses

3w+15

Back to the equation:

-(3w+15)



We add all the numbers together, and all the variables

-1w-(3w+15)-1=0

We get rid of parentheses

-1w-3w-15-1=0

We add all the numbers together, and all the variables

-4w-16=0

We move all terms containing w to the left, all other terms to the right

-4w=16

w=16/-4

w=-4

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